- Open Access
- Total Downloads : 261
- Authors : Xhevair Beqiri, Alit Ibraimi
- Paper ID : IJERTV2IS101178
- Volume & Issue : Volume 02, Issue 10 (October 2013)
- Published (First Online): 26-10-2013
- ISSN (Online) : 2278-0181
- Publisher Name : IJERT
- License: This work is licensed under a Creative Commons Attribution 4.0 International License
New oscillation criteria for second order advanced neutral differential equations
Xhevair Beqiri
State University of Tetova
Alit Ibraimi
State University of Tetova
Abstract
In this paper we present new criteria for oscillation of advanced neutral differential
A3) (t) C1 ([t
0
0
lim (t) .
t
, ),) , (t) t ,
equations second order of the form
[r(t)[((a(t)x(t) b(t)x( (t)) x(t t0 >0 (1)
where the coefficient r(t) is nonnegative continuous function , a(t), b(t) and c(t) are continuous function which filled certain conditions .
The conclusion is based also on building functions where are involved coefficients of
equation , positive functions (t) and the
In following we set
0z(t) a(t)x(t) b(t)x( (t)) . By a solution of equation (1) we consider a function
x(t), t [t x ,) [t0 ,} which is twice
continuously differentiable and satisfies equation
(1) on the given interval. We consider only non- trivial solutions . A solution x(t) of (1) is said to be oscillatory if there exists a sequence
n n1 0
n n1 0
{ } of points in the interval [t , }, such
positive function of Philo H (t, s) .
that lim and
n
n
n
x(n ) 0 ,
n N ,
Here , by using the generalized Riccati technique we get a new oscillation criteria for (1).
Key words: oscillation , differential equation, second order, interval, criteria etc.
Introduction
otherwise it is said to be non-oscillatory. An equation is said to be oscillatory if all its solutions are oscillatory, otherwise it is considered that is non-oscillatory solution .
Lemma 1. If x(t) is a positive solution of (1)
then exists t1 [t0 , ) such the corresponding function
Let consider and create new oscillation of
z(t) a(t)x(t) b(t)x( (t))
satisfies
(2)
advanced neutral differential equations second order of the form
t t1
z(t) 0 ,
z'(t) 0 ,
z''(t) 0 for
[r(t)((a(t)x(t) b(t)x( (t)) )']'c(t) x( (t) 0eventually.
Proof: Assume that the function x(t) is a
t t0
where is a quotient of odd positive integers and is a even number.
positive solution of (1) . Then from (1) follow that exists t1 [t0 , ) such that
We assume that
A1) a(t) 0 , c(t) 0 , 0 b(t) 1,
((r(t)(z'(t)) )' c(t) x( (t) 0
for
1
1
A2) r(t) 0 , 1
t t1
from where we get that the function
t0 r (s)
r(t)(z ' (t)) is decreasing for t t
1
and we
claim that r(t)(z ' (t)) 0 or
r(t)(z ' (t))
0 . If we let
r(t)(z ' (t)) 0
Since ''(w)
1
1
Aw
0 , we have
on t t1 then exists t2 t1 , such that 2
r(t)(z'(t)) r(t )(z'(t
2 2
))
0 , for all
that the function (w) attains to max value on
t t2 from where
1
at wmax , i. e. (wmax ) is a max value of function (w) and
1
1
z'(t) (r(t2 )) z'(t2 )
(r(t))
(wmax )
( 1)
1
B 1
A
and we can write the inequality
Integrating this from t2 to t we have
1
Bw Aw
B 1
.
1 t 1
( 1) 1 A
1
1
z(t) z(t2 ) (r(t2 ) z'(t2 ) ds
t2 (r(s))
Consider (2) we have
we can see that z(t) , where t .
x(t) 1 [z(t) b(t)x( (t))]
This contradicts because z(t) 0 we have
a(t)
r(t)(z ' (t)) 0 , from where z'(t) 0.
from where
From (1) we get
((r(t)(z'(t)) )' 0
r'(t)(z'(t)) r(t)(z't)) 1 z''(t) 0
from where
z''(t) 0.
This complete the proof.
1
x( (t)) 1 [z( (t)) b( (t))x( ( (t)))]
a( (t))
for x(t) 0 , (t) t and x'(t) 0 , also from (2) we get
x( (t)) x(t) and
x( (t)) z( (t))
finally
Lemma 2. Let () Bw Aw , A>0,
x( (t)) 1 [z( (t)) b( (t))z( (t))]
and B are constants, is a quotient of odd positive integers. Then function attains its
maximum value on at
x( (t))
a( (t))
1
[z( (t))(1 b( (t))] .wmax
B
( 1) A
and
Now define
a( (t))
1
r(t)(z'(t))
max( w) B .
w(t) v(t)
z ( (t))
, for
Proof.: From
( 1) 1
A
1 1
t t0 0
(3)
'(w) B
Aw
and
differenting (3) and using (1) we see that
w'(t) v'(t)
'(w) 0 , we get
w
( 1) 1
B 1
A .
r(t)(z'(t))
z ( (t))
-
v(t)
(r(t)z' (t))
z ( (t))
v(t)
r(t)z' (t)z 1 (t)z'( (t)) '(t)
z2 ( (t))
w'(t)
v'(t) w(t) v(t)
H (t, s)
t
p (t, s)
H (t, s)
and
v(t) c(t)(1 p( (t)) z' ( (t))
z'( (t)) '(t)
H (t, s) h (t, s)
H (t, s)
a ( (t))z ( (t))
w(t)
z( (t)) s 2
w'(t)
v'(t)
w(t)
Teorem 1. Assumed that A1) A3) hold
.Assume that exists a positive differentiable
v(t)
function v(t) and a function H (t, s) X and if
c(t)(1 p( (t))
1 '(t)
there exist (a, b) [t
, ),c (a, b) , such that
v(t) w(t)w (t) 0
a ( (t)) 1 1 c
c(t)(1 p( (t))
r ( (t))v (t)
1 [H (t, s)v(s)L(s)
H (c, a) a
for L(t)
a ( (t)) 0
H (t, s)v'(s) p (t, s) H (t, s) ]ds
we obtain
v'(t)
( 1) 1 v (s)H (t, s) ' (s)
c
c
1 b
w'(t)
w(t)
v(t)
H (b, c) [H (b, s)v(s)L(s)
1
'(t)
H (b, s)v'(s) h (b, s) H (b, s)
v(t)L(t) w
(t) 1 1
2 ]ds 0 (6)
( 1) 1 v (s)H (b, s) ' (s)
(4)
for
B v'(t) ,
r ( (t))v (t)
A '(t)
then every solution of eq. (1) is osillatory.
Proof: Suppose to the contrary, that x(t) be a non-oscillatory solution of (1) , say x(t) 0 on
v(t)
1 1
[t , ) from where z(t) 0 on [t , ) .v (t)r ( (t)) 0 0
we have
1(t )
If inequation (5) multiplying with H (t, s) and integrate from c to t where t (c, b), s (c, t)
we have
w'(t) v(t)L(t) B(t)w(t) A(t)w
now to consider lemma 2, we have t t
B 1
H (t, s)v(s)L(s)ds H (t, s)w'(s)ds
w'(t) v(t)L(t) c
( 1) 1 A
c
1
from where
t w'(s)
t W
(s) ' (s)H (t, s)
ds
ds
c
c
H (t, s) w(s) w(s)ds 1 1
(v'(t)) 1 r( (t))
w'(t) v(t)L(t)
( 1) 1 v (t)( '(t)) t
c r ( (s))v (s)
t
t t0 0
(5)
H (t, s)v(s)L(s)ds w(s)H (t, s)
We say that a function H (t, s) belons to the class X if
i) H C(D,[0, )) ;
-
H (t,t) 0 and H (t, s) 0 , for
s t ;
c
t
p (t, s)
c
t w'(s)
c
H (t, s)w(s)ds
1
t W (s) '(s)H (t, s)
-
H has continuous partial
H (t, s) w(s) w(s)ds 1
1 ds
c
derivatives on first and second variable
c r ( (s))v (s)
t t v'(s) c c v'(s)
H (t, s)v(s)L(s)ds w(c)H (t, c) [(H (t, s) v(s) H (s, t)v(s)L(s)ds w(c)H (s, t) [(H (s, t) v(s)
c c t t
-
h (t, s)
-
H (t, s))w(s) W
1
(s) '(s)H (t, s)]ds
1
W
W
(s) '(s)H (s, t)
2 1 1
p (s, t)
H (s, t))w(s) 1
1 ]ds
From Lemma2 for
r ( (s))v (s)
A '(s)H (t, s) ,
From Lemma2 for
r ( (s))v (s)
A '(s)H (s, t) ,
1 1 1 1
r ( (s))v (s)
r ( (s))v (s)
2
2
B H (t, s) v'(s) h (t, s)
H (t, s)
B H (s, t) v'(s) h (s,t)
H (s,t)
we have
t
v(s)
we have
c
v(s) 1
H (t, s)v(s)L(s)ds w(c)H (t, c)
c
H (s, t)v(s)L(s)ds w(c)H (s, t)
t
t H (t, s)v'(s) h (t, s)
H (t, s)
c H (s, t)v'(s) h (s, t)
H (s, t)
2
1
ds
(7)
1
1
ds
(9)
c ( 1) v (s)H
(t, s) ' (s)
t ( 1) v (s)H
(s, t) ' (s)
Let t a
in (9) ) and dividing it by H(c,a)
Let t b in (7 and dividing it by H(b,c) we get
we obtain
a
a
1 c
1 b
H (b, c) H (b, s)v(s)L(s)ds w(c)
H (c, a) H (t, s)v(s)L(s)ds w(c)
c 1 c H (t, s)v'(s) h (t, s)
H (t, s)
(10)
b H (b, s)v'(s) h (b, s) H (b, s)
1
1
ds
2 ds
c
c
( 1) 1 v (s)H (b, s) ' (s)
(8)
H (c, a) a ( 1)
v (s)H
(t, s) '
(s)
If (5)multiplying with
H (s, t)
and integrate
Adding (8) and (10) we have the following inequality
a
a
1 c
over (t, c) where t (a, c), s (t, c) we get
c c
H (c, a) [H (c, s)v(s)L(s)
H (s, t)v(s)L(s)ds H (s, t)w'(s)ds
H (c, s)v'(s) p (c, s) H (c, s) ]ds +
t t
1
( 1) 1 v (s)H (c, s) ' (s)
c w'(s)
c W
(s) ' (s)H (s, t) 1 b
H (s, t) w(s) w(s)ds 1
1 ds [H (b, s)v(s)L(s)
t t r ( (s))v (s)
H (b, c) c
c c c
H (b, s)v'(s) h (b, s)
H (b, s)
H (s, t)v(s)L(s)ds w(s)H (s, t)
t t
p (t, s)
t
H (s, t)w(s)ds
2
( 1) 1 v (s)H (b, s) ' (s)
]ds 0
c w'(s)
1
c W
(s) '(s)H (s, t)
Which contradict to the condition (6) , therefore
H (s, t) w(s) w(s)ds 1 1 ds
t t r ( (s))v (s)
, every solution of equation (1) be oscillatory . The proof is complete.
Corollary 1: Let assume that A1, A2, A3 hold. If
1 t
1 t
lim sup [(t s)v(s)L(s)
t
lim sup [H (t, s)v(s)L(s)
H (t, a)
t k
t k
(t s)v'(s) 1
H (t, s)v'(s) h (t, s)
H (t, s)
1
]ds
(15)
1 ]ds 0
(11)
( 1) v (s)(t s) '
(s)
0
0
( 1) 1 v (s)H (t, s) ' (s)
and
for any H X ,
v C1 ([t , ),(0, )) and
t
t
for all
1
k t0 , then every solution of (1) is
lim sup [H (t, s)v(s)L(s)
t H (t, c) k
oscillatory.
Proof: From (14) and (15) for
H (t, s)v'(s) p (t, s) H (t, s) ]ds 0
(12)
H (t, s)
H (t, s)
( 1) 1 v (s)H (t, s) ' (s)
t 1 ,
s 1
we have
0
0
for any H X , v C1 ([t , ),(0, )) and for all k t0 , then every solution of (1) is oscillatory.
Proof: For k t0 , from (11) if we take
k a , and c a , we get
1 c
lim sup [H (t, s)v(s)L(s)
t H (c, a) a
(14) respectively (15). The proof is complete.
Reference
-
J. Dzurina, Oscillation theorems for second order advanced neutral differential equations, Mathematical institute, Slovac Academy of sciences, 2011, p. 61- 71
-
Xh.Beqiri, E. Koci, Oscillation criteria for second order differential equations, British
Journal of Science, 2012, 73 -80.
H (t, s)v'(s) p (t, s) H (t, s)
[3]A. A. Soliman, R. A. Sallam, A. M. Hassan,( 1) 1 v (s)H (t, s) ' (s)]ds
(13)
Oscillation criteria of second order nonlinear neutral differential equations, International
journal of applied mathematical research, 2012,
From (12) for
1
k c
b
and for any
b c
p. 314 322.
[4] M. M. A. El-Sheikh, R. A. Sallam, D. I.lim sup [H (b, s)v(s)L(s)
t H (t, c) c
H (t, s)v'(s) p (t, s) H (t, s) ]ds 0
( 1) 1 v (s)H (t, s) ' (s)
If adding (12) to (13) ,we obtain the inequality of the theorem 1. Now, the proof is complete.
If for H (t, s) (t s) , t s t0 , we have the following corollary.
Corollary 1. Let assume that A1, A2, A3 hold. If
1 t
lim sup [(t s)v(s)L(s)
t
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[5]J. Dzurina, E. Thandapani, S. Tamilvanan, Oscillation of solutions to third- order half-linear neutral differential equations, electronic journal of differential equations, 2012, p. 1-9. [6]T. Li, E. Thandapani, J. Graef, Oscillation of third-order neutral retarded differential equations, international journal of pure and applied mathematics, 2012, p. 511 520. [7]Xh. Beqiri, New Oscillation Criteria For Second Order Nonlinear Differential Equations, reasearch inventy, International journal ofenginering and science, 2013,
t k
(t s)v'(s) 1
( 1) 1 v (s)(t s) ' (s)
and
]ds
(14)
p. 36 41.