- Open Access
- Total Downloads : 267
- Authors : Temitope Adefarati, Ayodele Sunday Oluwole, Kehinde Oluwafemi Olusuyi , Mufutau Adewolu Sanusi
- Paper ID : IJERTV2IS110313
- Volume & Issue : Volume 02, Issue 11 (November 2013)
- Published (First Online): 20-11-2013
- ISSN (Online) : 2278-0181
- Publisher Name : IJERT
- License: This work is licensed under a Creative Commons Attribution 4.0 International License
Economic and Industrial Application of Power Factor Improvement
Temitope Adefarati Department of Electrical/Electronic Engineering, Federal University Oye Ekiti, Nigeria
Ayodele Sunday Oluwole Department of Electrical/Electronic Engineering, Federal University Oye Ekiti, Nigeria
Kehinde Oluwafemi Olusuyi Physical Planning Unit, Federal University Oye Ekiti, Nigeria
Mufutau Adewolu Sanusi Department of Electrical/Electronic Engineering, Federal Polytechnic Ede Osun State Nigeria
Abstract
Power factor correction is a vital tool for maintaining the terminal voltage of an electrical system that operates at low power factor since any sudden change in power factor and current affect the terminal voltage of the system. If the power factor of any electrical system is improved to unity with the application of capacitors, the current of the same value of the power to be supplied is reduced to a minimum. This results in total reduction of power losses, terminal voltage drop and sizes of transformers, alternators, cables and switchgears. In order to encourage the large electricity end users to keep their loads at a unity or near unity power, electricity tariff is structured in such a way to depend on the consumers power factor. Power factor correction will result in reduction of maximum demand (KVA or KW) and affect the annual saving over the maximum demand charge. Also some expenditure will be incurred annually in the form of the interest and depreciation made over the power factor correcting equipment. Hence EEP computer application software was used to analyse the total cost that associated with power factor correction and annual saving with the application of power factor improvement. With this method, some percentage of money spent annually on electricity tariff will be reduced.
Keywords: Power factor, Active Power, Reactive Power, Apparent Power, Capacitor bank, Load
-
Introduction
During recent years, increasing attention has been paid to minimize the energy cost and inefficiency in electricity generation, transmission and distribution system [9]. When designing a compensation scheme; one should attempt to achieve the most economical solution in which the saving achieved in the equipment cost is significantly greater than the procurement cost of the reactive power [10].
Power factor is the cosine of the phase angle between voltage and current in an AC circuit. A very high capital cost of electrical power system materials such as switchers, alternators, transformers, and distribution and transmission lines is required to deliver the same amount of power at a low power factor. More energy losses occur at low power factor which result in poor efficiency and reliability of the system since energy losses are proportional to the square of the current [4]. Furthermore low voltage drop at low power factor leads to poor regulation; to keep the supply voltage within the permissible limit, a voltage regulating equipment must be installed [4]. This proofed to be an additional burden on the power end users that operate at low power factor. Having analyzed the drawback that associated with low power factor in electrical power system, the power utilities must impose a power factor of 0.8 and above on both industrial and domestic consumer/applications. With recent deregulation of power system all over the world, electricity tariffs are designed in such a way to penalize the consumers with low lagging power factor and encourage them to install power factor correction devices [4]. Hence the power factor of a system can be improved by connecting capacitors in star or delta in parallel with any equipment that is operating at a low power factor. This paper analyses power factor improvement in the industrial sector with application of capacitors. With application of power factor improvement, there will be a considerable reduction in heating of the power systems switchgears, alternators and transformers which will improve the efficiency and reliability of the power system [6]. Maintaining a high power factor in a power plant can yield direct saving such as reduced power bills, releases of system capacity, improves power system voltage, decreases power losses and make the system to be more efficient. The cost of improving the power factor in existing power plants depends on the value of the power factor selected and
equipment chosen to supply the compensating reactive power [I5].
-
Objectives of the research
The objectives of the research are as follows:
-
To formulate a mathematical model for optimization of electricity tariff in an industrial sector with the application of power factor improvement.
-
To estimate the annual power output in a power plant.
-
To estimate the annual power consumption of the consumers.
-
To develop the best approaches that will help power utility companies to improve power factor.
-
To see the effect of using penalty tariff to discourage application of reactive loads in the power system.
-
To introduce a computational approach for improvement of power factor in the industrial sector.
-
To reduce power losses in electrical power system with the application of power factor improvement.
-
To investigate current reduction and sizing of cables in power distribution systems.
-
To improve terminal voltage drop in a power system with the application of power factor improvement.
-
-
Power in AC Circuits
The product of voltage v and current i at any instant of time is called instantaneous power p, and is given by [2]:
P= vi 1
Let consider the average power P in a circuit that contains resistance and inductance.
P= 2
P= VmIm sinwt sin (wt –
p = VmIm {- [cos (wt+wt- – )]} 3 p= VmIm [cos ( -cos (2wt ) 4
Therefore
p= VmIm [cos -cos )] 5
Thus the average power VmImcos 6
P= xVmImcos ( 7
P = VI cos watts 8
Source: John Bird
Figure1: Waveform of power
Figure.1 is a power in an AC Circuit with resistance and inductive reactance. The waveforms of v, i and p, are shown in Figure 1 for an RL circuit. The waveform of power is seen to pulsate at twice the supply frequency [3].
-
Active Power
Active Power is the product of the applied voltage and active component of the current. From the power triangle as shown in fig 2, it is the real component of the apparent power. It is measured in watt or kW [3].
P=IVcos 9
-
Reactive Power
Reactive Power is the product of the applied voltage and reactive component of the current. From the power triangle as shown in fig 2, it is imaginary component of the apparent power. It is measured in Var or kVar [3]. P=IVsin 10
Effect of Reactive Power
The wattles or reactive power does no real work in a power system but on the other hand it increases the current taken by the load and reduces the power factor the circuit [3].
-
Apparent Power
Apparent Power is the product of r.m.s values of current and voltage. It is denoted by S and measure in VA or KVA [12].
Apparent Power = S 11
S=P±jQ 12
Where P is the active power and Q is the reactive power.
S= 13
S= 14
S= VI (cos +jsin) 15
-
-
Power Factor
Power Factor is the cosine of the phase angle between the applied voltage and the current drawn from the circuit. It varies from zero to unity. The power factor can be explained by the vectorial and sinusoidal relaions of power triangle as shown in figure 2. The term cos is known as power factor of the circuit. If the circuit is inductive, the current is lags behind the voltage and the power factor is called lagging power factor and if the circuit is capacitive then current leads the voltage and power factor is said to be leading power factor [7].
The low power factors problem can be solved by connecting power factor improvement capacitors in delta or star to the plant distribution system. Power factor correction capacitors reduce the total current drawn from the distribution system and subsequently increase the system's capacity by raising the power factor level [13].
Active power
Reactive Power
Apparent
Figure2.0: Power Triangle
Power factor is expressed as shown in equation 16
cos = 16
4.1 Advantages of power factor Improvement
-
It lowers transmission and distribution lines, transformers and alternators coppers losses.
-
Voltage improvement by lowering the terminal voltage drop at the transmission and distribution lines, transformers, alternators, bus bar etc.
-
Reduction of KVA demand charge for the large electricity consumers if a power factor penalty is introduced or the utility charges for maximum KVA demand is enforced.
-
Power factor improvement reduces load current.
-
Power factor correction reduces KVA loading of electrical equipment such as transformers and alternators which may relieve an overloaded system or release capacity for additional growth of load.
-
Power factor correction improves plant efficiency. Vii. Reduced overloading of cables, transformers, switchgears, alternators etc.
-
Tariff
The tariff is the rate of supplying electricity to various types of consumers i.e. Domestic consumers, Commercial consumers, Agricultural consumers and Industrial consumers [4]. Electricity charges for both industrial and commercial facilities consist of energy charge or the Kilowatt-hour charge which is directly proportional to the fuel used in producing and delivering that energy and demand rate i.e. kilowatt or KVA charge. This is usually related to the capital investment that must be made to build the generation, transmission and distribution facilities for delivering electrical energy to the consumers [15]. Electrical energy companies in the world incurred losses due to low power factor at the receiving ends especially for the bulk power consumers. To reduce the losses that associated with low power factor in a certain level, many countries in the world are undergoing power sector reform in order to make electricity to be more reliable. The tariff for various classes of electricity consumers who use a certain amount of electric energy is directly proportional to Kilowatt-hour (kWh) and maximum (KW) or (KVA) demand [2].
Monthly bill = N ( x KVA + y x KWh) 17
Where k is the charge per KVA maximum demand assessed and y is the charge per Kwh of energy consumed.
K= N38.50k
=N756. 00k
-
Power Factor Correction
Power factor improvement can be achieved by connecting static capacitors in parallel with the equipment that is operating at a lagging power factor. This results in a reduction of customer demand and energy charges [8]. Static capacitors have several benefits such as small losses or loss free, high efficiency, reliable, low capital cost, low maintenance cost and easy to install [4]. In three phase power system, capacitors can be connected in star or delta for power factor correction as shown in figure 3 and figure 4. The value of the static capacitors required for power factor improvement can be determined as follows:
Figure 3: Delta Connection of capacitors
26
Figure 4: Star Connection of capacitors
Active Power (KW)
o a
2
1
Apparent Reactive Power (Kvar) Power (KVA)
b
c
Figure5: Power Triangle
The leading KVar supplied by power factor correction equipment is given by bc as shown in figure.5.
bc = ac-ab
=Kvar1-Kvar2 18
= oaTan1-oaTan2 19
= oa (Tan1-Tan2) 20
= KW (Tan1-Tan2) 21
The value of capacitance needed for power factor correction is stated below
bc = IcV 22
Capacitor Cost/KVA = KW (Tan1-Tan2) A 27 If capacitor/KVA is represented by K where A is a fixed amount for loss free capacitor/KVA.
-
Depreciation
Depreciation is the loss in value resulting from the use of machinery and equipment during the period. During a specific period, the cost of using a capital good is the depreciation or loss of the value of that good, not its purchase price. The depreciation rate is the rate of such a loss in value [11].
Annual Depreciation Charges =
28
Percentage annual depreciation charges= x% 29
Salvage Value= 30
-
Interest
Nominal interest rate is the annual percentage increase in the nominal value of a financial asset [12].
Annual interest on capital cost =
Initial Cost x 31
Annual interest on capacitor cost =y% 32
Percentage annual saving in interest and depreciation rate = (x+y) % 33
=Z% 34
Percentage annual saving in interest and depreciation on the capacitor
= Z% KW (Tan1-Tan2) A 35
23
Capacitive reactance Xc
24
25
Figure.6: Independent Power plant and the off taker
The power plant has a combined installed capacity of 10 megawatts (MW) comprising of 2 units of 2MW diesel reciprocating engines and 4 units of 1.5MW gas reciprocating engines. The 10MW independent power is supplying public utilities based on the agreed tariff regime. The two outgoing feeders have separate energy meters for their respective monthly reading. To reduce the effect of penalty tariff introduced by the by the independent power plant, the off taker had to be operating at a power factor above 0.8, this can only be achieved with the application of power factor device
.Hence this paper actually studied the effect of installing power factor correction device in any power system.
-
Estimation of KVAR required for power factor improvement.
Estimation of capacitive KVAR required for power factor improvement at a given load can be achieved with application of EEP power factor correction application software as shown in figures 7&8. The static capacitor rating must be carefully selected having considered rated voltage of the power system and the system over voltages.
-
Main Template
The function of the main template is to accept the necessary data such as frequency, input power, old and new power factor, type of capacitor connection and daily working hours just as it reflects in fig. 7. All this data is required for calculation of annual cost before power factor correction, annual Cost after power factor correction and annual saving.
Source:EEP computer application software
Figure.7:Main Template
6.1Result Template
The function of the main template is to accept the necessary data such as frequency, input power, old and new power factor, type of capacitor connection and daily working hours just as it reflects in fig. 8. All this data is required for calculation of annual cost before power factor correction, annual Cost after power factor correction and annual saving.
Source:EEP computer application software
Figure.8:Result Template
-
Power losses in Electrical Power Systems: Power losses in electrical transmission and distribution systems can be reduced by connecting static capacitors either in star or delta to the system. This will result in
an increase in the system power factor. The total power loss in any electrical system is a summation of alternators losses, transformers losses, bus bar losses and cable losses. The reduction can only be achieved by reducing the currentflowing in the alternators, transformers, bus bars and cables. The power loss is expressed as shown in equation 36
P= 36
% Power loss reduction =
= 37
drastically reduce the terminal voltage at the receiving end i.e. transformers, switchgears and motor control centers. The formula for calculating voltage drop in electrical cable is shown in equation 45.
= 38
= (1- 39
= {1-( ) 2}*100% 40
= (1- 41
= 100% 42
= 100% 43
-
Current Reduction
Power factor correction reduces the current drawn from the electrical power system and increases the system's capacity by raising the power factor to a certain level. This will allow extra loads to be served by the same power system. Some electrical equipment such transformers, cables, alternators, distribution and transmission lines which might have been thermally overloaded when operating at low power factor will now be operating optimally with application of power factor improvement which is the best option of reducing current flowing through these equipment to a certain level [15]. Power factor improvement is the appropriate and economic way to reduce current and overloading of cables, transformers, alternators, and transmission and distribution lines. This is illustrated by the relationship shown in equation 44
44
Current reduction will reduce the sizes of cable and bus bar to be connected in power distribution systems.
-
Voltage Improvement
Power factor improvement will optimize a circuit voltage, for this reason it is necessary to install static capacitors in star or delta for power factor improvement. Power factor improvement will affect the voltage drop in any electrical cable, thus this will
45
The size of cables is selected by dividing the rated load current by different correction factors, K1, K2, K3, K4, and K5——-
= 46
Where K1, K2, K3, K4, K5 —— are correction factors
K1 is the Correction factors for ambient air temperatures other than 30 °C to be applied to the current-carrying capacities for cables in the air Ground Temperature Correction Factor K2=0. 93
Soil Correction Factor for Air K3 = 1.00
Group Factor for Ground K4= 1.00
Cable Laying Depth Factor K5 = 0.98
Total derating Factor= 0.91
K1xK2xK3xK4 =1. 0x0.93 x1. 0x1.0x0.91 = 0.91
47
=IZL
Where Z =Impedance, /km L=Distance
I=Full load current
Due to power factor improvement, the new voltage drop can be estimated by using equation x
% Voltage Drop = x100% 47
Figure.9 illustrates application of EEP application software for selection of cables.
Figure.10 illustrates %voltage drop in a cable having considered the different power factor and correction factors.
8.0 Result and discussions
Table1:Total annual cost per year without application of power factor improvement.
Year |
2008 |
2009 |
2010 |
2011 |
2012 |
Active Power(kw) |
6300 |
6500 |
7000 |
7800 |
8000 |
Old Maximum KVA |
8750 |
9155 |
9210.5 |
10000 |
10126.6 |
Old Power Factor (Cos1) |
0.72 |
0.71 |
0.76 |
0.78 |
0.79 |
KVA Demand Charge (N:K) |
8750 |
6921126.8 |
6963157.9 |
7560000 |
7655696.2 |
Unit Consumed/Year(Kwh) |
55188000 |
56940000 |
61320000 |
68328000 |
70080000 |
Energy Charge /Year(N:K) |
1931580000 |
1992900000 |
2146200000 |
2391480000 |
2452800000 |
Total Annual Cost(N:K) |
1938195000 |
1999821127 |
2153163158 |
2399040000 |
2460455696 |
Table.1 shows the total annual cost per year without application of power factor improvement.The table illustrates the KVA demand charge,unit consumed
,energy charge and total annual cost per year for an independent power plant as shown in figure6.
Table.2: The annual saving after the
Year |
2008 |
2009 |
2010 |
2011 |
2012 |
Active Power (Kw) |
6300 |
6500 |
7000 |
7800 |
8000 |
New Max KVA |
6847.8 |
6989.2 |
7526.9 |
8387 |
8602.2 |
New Power (Cos2) |
0.92 |
0.93 |
0.93 |
0.93 |
0.93 |
Tariff Charge/KVA |
756 |
756 |
756 |
756 |
756 |
Tariff Charge/Kw |
35 |
35 |
35 |
35 |
35 |
Capacitor Cost/KVA |
60 |
60 |
60 |
60 |
60 |
Leading Kvar |
3388.484 |
3877.952 |
3219.557 |
3175.038 |
3046.875 |
Annual Interest & Depreciation |
8% |
8% |
8% |
8% |
8% |
KVA Demand Charge |
5176956.5 |
5283871 |
5690322.6 |
6340645.2 |
6503225.8 |
Unit Consumed/Year |
55188000 |
56940000 |
61320000 |
68328000 |
70080000 |
Energy Charged/Year |
1931580000 |
1992900000 |
2146200000 |
239148000 |
2452800000 |
Total Annual cost |
1936756957 |
1998183871 |
2151890323 |
2397820645 |
2459303226 |
Capital cost of Capacitor |
203309.1 |
232677 |
193173.4 |
190502.3 |
182812.5 |
Annual Depreciation /Capacitor |
16264.72 |
18614.17 |
15453.87 |
15240.18 |
14625 |
Annual Cost before Power factor correction |
1938195000 |
1999821127 |
2153163158 |
2399040000 |
2460455696 |
Annual Cost after power factor correction |
1936773221 |
1998202485 |
2151905776 |
2397835885 |
2459317851 |
Annual Saving |
1421778.8 |
1618641.6 |
1257381.4 |
1204114.7 |
1137845.4 |
Year |
2008 |
2009 |
2010 |
2011 |
2012 |
Active Power (Kw) |
6300 |
6500 |
7000 |
7800 |
8000 |
New Max KVA |
6847.8 |
6989.2 |
7526.9 |
8387 |
8602.2 |
New Power (Cos2) |
0.92 |
0.93 |
0.93 |
0.93 |
0.93 |
Tariff Charge/KVA |
756 |
756 |
756 |
756 |
756 |
Tariff Charge/Kw |
35 |
35 |
35 |
35 |
35 |
Capacitor Cost/KVA |
60 |
60 |
60 |
60 |
60 |
Leading Kvar |
3388.484 |
3877.952 |
3219.557 |
3175.038 |
3046.875 |
Annual Interest & Depreciation |
8% |
8% |
8% |
8% |
8% |
KVA Demand Charge |
5176956.5 |
5283871 |
5690322.6 |
6340645.2 |
6503225.8 |
Unit Consumed/Year |
55188000 |
56940000 |
61320000 |
68328000 |
70080000 |
Energy Charged/Year |
1931580000 |
1992900000 |
2146200000 |
239148000 |
2452800000 |
Total Annual cost |
1936756957 |
1998183871 |
2151890323 |
2397820645 |
2459303226 |
Capital cost of Capacitor |
203309.1 |
232677 |
193173.4 |
190502.3 |
182812.5 |
Annual Depreciation /Capacitor |
16264.72 |
18614.17 |
15453.87 |
15240.18 |
14625 |
Annual Cost before Power factor correction |
1938195000 |
1999821127 |
2153163158 |
2399040000 |
2460455696 |
Annual Cost after power factor correction |
1936773221 |
1998202485 |
2151905776 |
2397835885 |
2459317851 |
Annual Saving |
1421778.8 |
1618641.6 |
1257381.4 |
1204114.7 |
1137845.4 |
power factor improvement device has been applied.
Table.2 illustrates the annual saving after the power factor improvement device has been applied by the consumers of the power plant shown figurey. The table also illustrates different parameters that have to do with power factor correction such as Capital cost of the capacitor, annual Depreciation /Capacitor, annual cost before power factor correction, the annual cost after power factor correction and annual saving.
Figure.10:Annual cost before and after application of power factor improvement.
The figure compares and constracts annual cost before and after application of power factor correction.The
saving incured from application of power factor improvement is also analysed.
Figure 11 shows the annual saving per year
Time |
Old PF |
Desired PF |
% Power Loss Reductio |
0 |
0.78 |
0.82 |
9.518144 |
2 |
0.79 |
0.86 |
15.61655 |
4 |
0.8 |
0.88 |
17.35537 |
6 |
0.82 |
0.9 |
16.98765 |
8 |
0.85 |
0.92 |
14.63847 |
10 |
0.88 |
0.94 |
12.35853 |
12 |
0.86 |
0.91 |
10.68712 |
14 |
0.84 |
0.93 |
18.41831 |
18 |
0.88 |
0.95 |
14.19391 |
20 |
0.89 |
0.96 |
14.05165 |
22 |
0.87 |
0.97 |
19.55574 |
24 |
0.86 |
0.94 |
16.29697 |
Time |
Old PF |
Desired PF |
% Power Loss Reductio |
0 |
0.78 |
0.82 |
9.518144 |
2 |
0.79 |
0.86 |
15.61655 |
4 |
0.8 |
0.88 |
17.35537 |
6 |
0.82 |
0.9 |
16.98765 |
8 |
0.85 |
0.92 |
14.63847 |
10 |
0.88 |
0.94 |
12.35853 |
12 |
0.86 |
0.91 |
10.68712 |
14 |
0.84 |
0.93 |
18.41831 |
18 |
0.88 |
0.95 |
14.19391 |
20 |
0.89 |
0.96 |
14.05165 |
22 |
0.87 |
0.97 |
19.55574 |
24 |
0.86 |
0.94 |
16.29697 |
Before Application of power factor improvement |
|||||
Time |
Old PF |
P(KW )@41 5V |
Q(Kvar) |
S(KVA) |
I (A) |
0 |
0.78 |
6000 |
4813.7 |
7692.3 |
10701.9 |
2 |
0.79 |
5560 |
4315.1 |
7038 |
9791.56 |
4 |
0.8 |
6500 |
4875 |
8125 |
11303.9 |
6 |
0.82 |
6800 |
4746.5 |
8292.7 |
11537.2 |
8 |
0.85 |
7000 |
4338.2 |
8235.3 |
11457.3 |
10 |
0.88 |
7250 |
3913.1 |
8238.6 |
11462 |
12 |
0.86 |
7500 |
4450.2 |
8720.9 |
12133 |
14 |
0.84 |
7800 |
5038.3 |
9285.7 |
12918.7 |
18 |
0.88 |
7900 |
4264 |
8977.3 |
12490 |
20 |
0.89 |
8000 |
4098.6 |
8988.8 |
12505.6 |
22 |
0.87 |
7650 |
4335.4 |
8793.1 |
12233.4 |
24 |
0.86 |
7600 |
4307.2 |
8735.7 |
12153.4 |
Before Application of power factor improvement |
|||||
Time |
Old PF |
P(KW )@41 5V |
Q(Kvar) |
S(KVA) |
I (A) |
0 |
0.78 |
6000 |
4813.7 |
7692.3 |
10701.9 |
2 |
0.79 |
5560 |
4315.1 |
7038 |
9791.56 |
4 |
0.8 |
6500 |
4875 |
8125 |
11303.9 |
6 |
0.82 |
6800 |
4746.5 |
8292.7 |
11537.2 |
8 |
0.85 |
7000 |
4338.2 |
8235.3 |
11457.3 |
10 |
0.88 |
7250 |
3913.1 |
8238.6 |
11462 |
12 |
0.86 |
7500 |
4450.2 |
8720.9 |
12133 |
14 |
0.84 |
7800 |
5038.3 |
9285.7 |
12918.7 |
18 |
0.88 |
7900 |
4264 |
8977.3 |
12490 |
20 |
0.89 |
8000 |
4098.6 |
8988.8 |
12505.6 |
22 |
0.87 |
7650 |
4335.4 |
8793.1 |
12233.4 |
24 |
0.86 |
7600 |
4307.2 |
8735.7 |
12153.4 |
Table4: Effect of power factor correction on I and S
Table 3: Hourly reduction of power losses
The table shows the hourly reduction in power losses in the independent power plant shows in figure 6 with application of power factor correction device.
Figure 12 shows the hourly power loss reduction with application of power factor improvement.
The table shows the effect of power correction on current and apparent power before application of power factor correction.
Table 5: Effect of power factor correction on I and S after application of power factor improvement.
After Application of power factor improvement |
|||||
T |
P(KW) @415V |
Desired PF |
Q(Kvar) |
S(KVA) |
I (A) |
0 |
6000 |
0.82 |
4188.07 |
7317.1 |
10180 |
2 |
5560 |
0.86 |
3299.08 |
6465.1 |
8994.5 |
4 |
6500 |
0.88 |
3856.8 |
7558.1 |
10515 |
6 |
6800 |
0.9 |
2896.78 |
7391.3 |
10283 |
8 |
7000 |
0.92 |
2982 |
7608.7 |
10586 |
10 |
7250 |
0.94 |
2631.5 |
7712.8 |
10730 |
12 |
7500 |
0.91 |
3417.2 |
8241.8 |
11466 |
14 |
7800 |
0.93 |
3082.77 |
8387.1 |
11669 |
18 |
7900 |
0.95 |
2596.64 |
8315.8 |
11569 |
20 |
8000 |
0.96 |
2333.21 |
8333.3 |
11594 |
22 |
7650 |
0.97 |
1917.28 |
7886.6 |
10972 |
24 |
7600 |
0.94 |
2758.41 |
8085.1 |
11248 |
Table 6 shows the effect of power correction on current and apparent power after application of power factor correction.
Figure 13 illustrate power factor per hour.
Figure 14 shows the effect of power factor on apparent power.The figure shows that with application of power factor improvement there will be total reduction in apparent power of the power sysytem.
Figure 15 shows the effect of power factor correction on the current drawn from the electrical power system. The figure compares the effect of current before and after application of power factor correction.
Table6: Voltage drops in a cable with application of power factor improvement.
The shows the voltage improvement by considering a unit (2MW) in the power plant as shown in fig. 6. To
Active Power (Kw) |
Desired Power factor |
Voltage Drop% |
Size of cable(XLPE LV) |
2000 |
0.8 |
0.74 |
6x500mm2 |
2000 |
0.82 |
0.71 |
6x500mm2 |
2000 |
0.84 |
0.68 |
6x500mm2 |
2000 |
0.86 |
0.66 |
6x500mm2 |
2000 |
0.88 |
0.63 |
6x500mm2 |
2000 |
0.9 |
0.6 |
6x500mm2 |
2000 |
0.92 |
0.57 |
6x500mm2 |
2000 |
0.94 |
0.53 |
6x500mm2 |
2000 |
0.96 |
0.49 |
6x500mm2 |
2000 |
0.98 |
0.44 |
6x500mm2 |
improve voltage in a power system, the system must be operating at unity or near unity power factor. In order to achieve this, power factor improvement device must be connected in parallel with the system. From Table 3, voltage drop is inversely proportional to power factor.
Figure5 shows the percentage of voltage drop in a cable.Voltage drop is inversely proportional to power factor.
9.0 Conclusion
The low power factor in any electrical power system causes an increase in KVA demand charge the electricity consumers by the utilities. Hence, in order to ensure most favorable conditions for a power system in both engineering and economic perspective, it is important for any power system with different equipment such as alternators, transformers, switchgears, and transmission and factory or very close to unity power factor. With this, total reduction in the cost of electricity can be achieved in economic and efficient way. Having analyzed different cases from
this research work, it has been established that in order to have good performance of the electric power system, it is important to operate the system between the power factor of 0.8 and 1.0. This will reduce power losses and improve terminal voltage without the need
To install additional auxiliaries such as transformer cables, switchgears, alternators, bus bars etc. Hence power factor improvement results in:
-
Improve voltage drop.
-
Improved plant efficiency and reliability.
-
Reduced overloading (Current Reduction) of cables, transformers, switchgear, bus bar etc.
-
Reduced power losses in power system
-
Reduced electricity charge per month or annum.
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